Optimal. Leaf size=133 \[ \frac{2 a^2 (5 A+4 C) \tan (c+d x)}{5 d \sqrt{a \sec (c+d x)+a}}+\frac{2 a^{3/2} A \tan ^{-1}\left (\frac{\sqrt{a} \tan (c+d x)}{\sqrt{a \sec (c+d x)+a}}\right )}{d}+\frac{2 a C \tan (c+d x) \sqrt{a \sec (c+d x)+a}}{5 d}+\frac{2 C \tan (c+d x) (a \sec (c+d x)+a)^{3/2}}{5 d} \]
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Rubi [A] time = 0.222669, antiderivative size = 133, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.222, Rules used = {4055, 3917, 3915, 3774, 203, 3792} \[ \frac{2 a^2 (5 A+4 C) \tan (c+d x)}{5 d \sqrt{a \sec (c+d x)+a}}+\frac{2 a^{3/2} A \tan ^{-1}\left (\frac{\sqrt{a} \tan (c+d x)}{\sqrt{a \sec (c+d x)+a}}\right )}{d}+\frac{2 a C \tan (c+d x) \sqrt{a \sec (c+d x)+a}}{5 d}+\frac{2 C \tan (c+d x) (a \sec (c+d x)+a)^{3/2}}{5 d} \]
Antiderivative was successfully verified.
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Rule 4055
Rule 3917
Rule 3915
Rule 3774
Rule 203
Rule 3792
Rubi steps
\begin{align*} \int (a+a \sec (c+d x))^{3/2} \left (A+C \sec ^2(c+d x)\right ) \, dx &=\frac{2 C (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{5 d}+\frac{2 \int (a+a \sec (c+d x))^{3/2} \left (\frac{5 a A}{2}+\frac{3}{2} a C \sec (c+d x)\right ) \, dx}{5 a}\\ &=\frac{2 a C \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{5 d}+\frac{2 C (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{5 d}+\frac{4 \int \sqrt{a+a \sec (c+d x)} \left (\frac{15 a^2 A}{4}+\frac{3}{4} a^2 (5 A+4 C) \sec (c+d x)\right ) \, dx}{15 a}\\ &=\frac{2 a C \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{5 d}+\frac{2 C (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{5 d}+(a A) \int \sqrt{a+a \sec (c+d x)} \, dx+\frac{1}{5} (a (5 A+4 C)) \int \sec (c+d x) \sqrt{a+a \sec (c+d x)} \, dx\\ &=\frac{2 a^2 (5 A+4 C) \tan (c+d x)}{5 d \sqrt{a+a \sec (c+d x)}}+\frac{2 a C \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{5 d}+\frac{2 C (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{5 d}-\frac{\left (2 a^2 A\right ) \operatorname{Subst}\left (\int \frac{1}{a+x^2} \, dx,x,-\frac{a \tan (c+d x)}{\sqrt{a+a \sec (c+d x)}}\right )}{d}\\ &=\frac{2 a^{3/2} A \tan ^{-1}\left (\frac{\sqrt{a} \tan (c+d x)}{\sqrt{a+a \sec (c+d x)}}\right )}{d}+\frac{2 a^2 (5 A+4 C) \tan (c+d x)}{5 d \sqrt{a+a \sec (c+d x)}}+\frac{2 a C \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{5 d}+\frac{2 C (a+a \sec (c+d x))^{3/2} \tan (c+d x)}{5 d}\\ \end{align*}
Mathematica [A] time = 1.1978, size = 122, normalized size = 0.92 \[ \frac{a \tan \left (\frac{1}{2} (c+d x)\right ) \sec ^2(c+d x) \sqrt{a (\sec (c+d x)+1)} \left (\sqrt{\sec (c+d x)-1} ((5 A+6 C) \cos (2 (c+d x))+5 A+6 C \cos (c+d x)+8 C)+10 A \cos ^2(c+d x) \tan ^{-1}\left (\sqrt{\sec (c+d x)-1}\right )\right )}{5 d \sqrt{\sec (c+d x)-1}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.295, size = 330, normalized size = 2.5 \begin{align*} -{\frac{a}{20\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}\sin \left ( dx+c \right ) }\sqrt{{\frac{a \left ( \cos \left ( dx+c \right ) +1 \right ) }{\cos \left ( dx+c \right ) }}} \left ( 5\,A\sin \left ( dx+c \right ) \sqrt{2}{\it Artanh} \left ( 1/2\,{\frac{\sqrt{2}\sin \left ( dx+c \right ) }{\cos \left ( dx+c \right ) }\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}}}} \right ) \left ( -2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}} \right ) ^{5/2} \left ( \cos \left ( dx+c \right ) \right ) ^{2}+10\,A\sin \left ( dx+c \right ) \sqrt{2}{\it Artanh} \left ( 1/2\,{\frac{\sqrt{2}\sin \left ( dx+c \right ) }{\cos \left ( dx+c \right ) }\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}}}} \right ) \left ( -2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}} \right ) ^{5/2}\cos \left ( dx+c \right ) +5\,A{\it Artanh} \left ( 1/2\,{\frac{\sqrt{2}\sin \left ( dx+c \right ) }{\cos \left ( dx+c \right ) }\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}}}} \right ) \sqrt{2} \left ( -2\,{\frac{\cos \left ( dx+c \right ) }{\cos \left ( dx+c \right ) +1}} \right ) ^{5/2}\sin \left ( dx+c \right ) +40\,A \left ( \cos \left ( dx+c \right ) \right ) ^{3}+48\,C \left ( \cos \left ( dx+c \right ) \right ) ^{3}-40\,A \left ( \cos \left ( dx+c \right ) \right ) ^{2}-24\,C \left ( \cos \left ( dx+c \right ) \right ) ^{2}-16\,C\cos \left ( dx+c \right ) -8\,C \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.566698, size = 887, normalized size = 6.67 \begin{align*} \left [\frac{5 \,{\left (A a \cos \left (d x + c\right )^{3} + A a \cos \left (d x + c\right )^{2}\right )} \sqrt{-a} \log \left (\frac{2 \, a \cos \left (d x + c\right )^{2} - 2 \, \sqrt{-a} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \cos \left (d x + c\right ) \sin \left (d x + c\right ) + a \cos \left (d x + c\right ) - a}{\cos \left (d x + c\right ) + 1}\right ) + 2 \,{\left ({\left (5 \, A + 6 \, C\right )} a \cos \left (d x + c\right )^{2} + 3 \, C a \cos \left (d x + c\right ) + C a\right )} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \sin \left (d x + c\right )}{5 \,{\left (d \cos \left (d x + c\right )^{3} + d \cos \left (d x + c\right )^{2}\right )}}, -\frac{2 \,{\left (5 \,{\left (A a \cos \left (d x + c\right )^{3} + A a \cos \left (d x + c\right )^{2}\right )} \sqrt{a} \arctan \left (\frac{\sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \cos \left (d x + c\right )}{\sqrt{a} \sin \left (d x + c\right )}\right ) -{\left ({\left (5 \, A + 6 \, C\right )} a \cos \left (d x + c\right )^{2} + 3 \, C a \cos \left (d x + c\right ) + C a\right )} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \sin \left (d x + c\right )\right )}}{5 \,{\left (d \cos \left (d x + c\right )^{3} + d \cos \left (d x + c\right )^{2}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (a \left (\sec{\left (c + d x \right )} + 1\right )\right )^{\frac{3}{2}} \left (A + C \sec ^{2}{\left (c + d x \right )}\right )\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: NotImplementedError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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